With a maximum of two games remaining in the 2013 World Series this is the last installment of the reverse engineered game odds. The only unknown left is the odds for Game #7. The Game #6 odds and the final series winner odds are both out and from those two knowns we can reverse engineer what the Game #7 odds are (or should be).
Individual Game Odds
| Game # | Red Sox | Cardinals |
|---|---|---|
| Game 1 | 100% | 0% |
| Game 2 | 0% | 100% |
| Game 3 | 0% | 100% |
| Game 4 | 100% | 0% |
| Game 5 | 100% | 0% |
| Game 6 | 53.16% | 46.84% |
| Game 7 | 55.75% | 44.25% |
| Series | 79.27% | 20.73% |
And using the nifty spreadsheet calculator that one of my readers made for me, we can also see the chances that each team wins the series in X number of games. There are only three possible outcomes left obviously and they are the Red Sox winning in six or seven games or the Cardinals winning in seven games. Here is another table showing those odds.
| Result | Chance % | Odds |
|---|---|---|
| 79.27% | ||
| Red Sox in 4 | 0.0% | NA |
| Red Sox in 5 | 0.0% | NA |
| Red Sox in 6 | 53.16% | 0.88 |
| Red Sox in 7 | 26.11% | 2.83 |
| 20.73% | ||
| Cardinals in 4 | 0.0% | NA |
| Cardinals in 5 | 0.0% | NA |
| Cardinals in 6 | 0.0% | NA |
| Cardinals in 7 | 20.73% | 3.82 |
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